tan(pie/4 + theta) with explain
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Answered by
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Hey !!
tan(π/4 + ¢ ) = tan(45° + ¢ )
tan(45° + ¢ ) = tan45° + tan¢ /1 - tan¢ × tan45°
but tan45° = 1
so, 1 + tan¢ /1 - tan¢ × 1
=> 1 + tan¢ /1 - tan¢ Answer
***************************************
Hope it helps you !!!
@Rajukumar111

tan(π/4 + ¢ ) = tan(45° + ¢ )
tan(45° + ¢ ) = tan45° + tan¢ /1 - tan¢ × tan45°
but tan45° = 1
so, 1 + tan¢ /1 - tan¢ × 1
=> 1 + tan¢ /1 - tan¢ Answer
***************************************
Hope it helps you !!!
@Rajukumar111
clpm444p7j3f4:
Most thanks You
Answered by
1
= (1+tan Ф)/(1- tanФ)
Please refer picture for detailed solution
Please refer picture for detailed solution
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