Question

Tan power4o +tan power2=sec power 4-sec power 2

Answer 1

Answer:

PLEase refer the attachment..

Answer 2

$LHS = tan^{4} A + tan^{2}A\\= tan^{2} A( tan^{2}A + 1)\\= tan^{2}A\times sec^{2}A$

$\boxed { \pink {Since, tan^{2}A +1 = sec^{2}A }}$

$= ( sec^{2}A - 1 )sec^{2}A \\= sec^{4}A - sec^{2} A \\= RHS$

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