:)
tan
Prove that on 70° - tan 20° =
2 tan 50°
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tan70°=tan(50°+20°)
using formula :
tan(A+B)= tanA+tanB1−tanAtanB
tan70°=tan50°+tan20°1−tan50°×tan20°
tan70°−tan70°tan50°tan20°=tan50°+tan20°
tan70°=tan20°+tan50°+tan70°tan50°tan20°
tan70°=tan20°+tan50°(1+tan70°tan20°)
tan70°=tan20°+tan50°(1+tan(90°−20°)×tan20°)
tan70°=tan20°+tan50°(1+cot20°tan20°)
tan70°=tan20°+tan50°(1+tan20°tan20°)
Since (cotθ=1tanθ)
tan70°=tan20°+tan50°(1+1)
tan70°=tan20°+2tan50°
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