Question

Tan× + sec× - 1 / tan×- sec× + 1 = sin× + 1 / cos×

Answer 1

Step-by-step explanation:

tanx+secx-1/tanx-secA+1

=(tanx+secx-1)(tanx+secx)/ (tanx-secx+1)(tanx+secx)

=(tanx+secx-1)(tanx+secx)/ (tan²x-sec²x)+(tanx+secx)

=(tanx+secx-1)(tanx+secx)/ -1+tanx+secx

=tanx+secx

=sinx/cosx+1/cosx

=1+sinx/cosx