Question

(tan + sec ) ^2 = 1+ sin / 1- sin​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

LHS = (tanA + secA)^2

= {( sinA / cosA) + (1 / cosA )}^2

= { (1 + sinA ) / cosA }^2

={(1 + sinA)^2} / cos²A  

= (1 + sinA)²/1 - sin²A

= (1 + sinA)²/ (1 + sinA ) (1 - sinA)

= (1 + sinA)/(1 - sinA) RHS proved  

Step-by-step explanation:

step 1 = change the Tan and Sec into sin And Cos

step 2 = Take the LCM between the fractions

step 3 =  change the cos²A into 1 - sin²A

step 4 = put it in the formula of a² - b²