tan + seco - 1÷tano - seco + 1.1)tan÷sin 2)seca÷1+ sin 3)1+ sin÷cos 4)cos÷ 1+ sin
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Answer:
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Step-by-step explanation:
(a+b)
3
(a
4
+b
4
)
sinθ.sec
7
θ+cosθ.cosec
7
θ
=tanθ.sec
6
θ+cotθ.cosec
6
θ.
=tanθ(1+tan
2
θ)
3
+cotθ(1+cot
2
θ)
3
=
b
a
(1+
b
a
)
3
+
a
b
(1+
a
b
)
3
Upon simplifying, we get
(ab)
2
7
(a+b)
3
(a
4
+b
4
)
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