Question

tan + sin = m and tan - sin = n, the m^2 - n^2is equal to?
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Answer 1

Answer:

Step-by-step explanation:

a^-b^2=(a+b)*(a-b)

hence m^2-n^2=(m+n) (m-n)

=(tan+sin+tan-sin) (tan+sin-tan+sin)=2tan*2sin

4tan*sin

Answer 2

Answer:

a^-b^2=(a+b)*(a-b)

hence m^2-n^2=(m+n) (m-n)

=(tan+sin+tan-sin) (tan+sin-tan+sin)=2tan*2sin

4tan*sin

Step-by-step explanation: