Math, asked by goldendew, 4 months ago

tan+sin0/tan0-sin0=sec0+1/sec-1

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Answered by PallaviVerma24

6

Answer:

LHS=sin0-cos0+1/sin0+cos0-1

on dividing by cos0 up and down,then

tan0+se0-1/tan0-sec0+1

= sec0+tan0-(sec20-tan20)/tan0-sec0+1

= sec0+tan0-{(sec0+tan0)(sec0-tan0)}/tan0-sec0+1

=sec0+tan0(1-sec0+tan0)/tan0-sec0+1

=sec0+tan0*(sec0-tan0)/(sec0-tan0)

=(sec20-tan20)/(sec0-tan0)

=1/sec0-tan0)

=RHS

Step-by-step explanation:

Please make me brainlist.

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