tan sq theata + cot sq theata + 2 =sec sq theata cosec sq theata
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yes it us its identity
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=(tanx+cotx)^2=(sinx/coax+cosx/sinx)^2
by taking LCM (sin^2x+cos^2x)^2/(sinx×cosx)^2
=1/sin^2x×cos^2x=sec^2x×cosec^2x
by taking LCM (sin^2x+cos^2x)^2/(sinx×cosx)^2
=1/sin^2x×cos^2x=sec^2x×cosec^2x
Nina1483:
what about the +2 in the tan sq theata + cot sq theata + 2
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