Question

tan square 60 degree upon 1 - sin square 60 degree please tell me this question​

Answer 1

Answer:

$\frac{ {tan}^{2}60 }{1 - {sin}^{2}60 } \\ = \frac{ { (\sqrt{3}) }^{2} }{1 - ({ \frac{ \sqrt{3} }{2}) }^{2} } \\ = \frac{3}{1 - \frac{3}{4} } \\ = \frac{3 \times 4}{4 - 3} \\ = 12$

Answer 2

Answer:

12 is the answer.......................