Question

tan square A - sin square A = tan square A sin square A​

Answer 1

i hope this helps you mate

Answer 2

Answer:

Taking LHS :-

sin^2A / cos^2A - sin^2A

sin^2A - sin^2A X cos^2A / cos^2A

by taking sin^2A common we get,

sin^2A ( 1 - cos^2A ) / cos^2A

( sin^2A ) (sin^2A) / cos^2A

by separating them we get,

sin^2A / cos^2A X sin^2A

tan^2A X sin^2A

hence, LHS=RHS

hope it helps ....