Question

tan square theta +( 1 -√3) tan theta -√ 3 = 0​

Answer 1

Answer:

hope this answer help you dear

Answer 2

Step-by-step explanation:

$\tan^{2} \alpha + (1 - \sqrt{3} ) \tan( \alpha ) - \sqrt{3 } = 0 \\ \tan^{2} \alpha + \tan( \alpha ) - \sqrt{3} \tan( \alpha ) - \sqrt{3} = 0 \\ \tan( \alpha ) ( \tan( \alpha ) + 1) - \sqrt{3} (\tan( \alpha ) + 1) = 0 \\ (\tan( \alpha ) + 1)( \tan( \alpha ) - \sqrt{3} ) = 0 \\ if(\tan( \alpha ) + 1) = 0 \\ \tan( \alpha ) = - 1 \\ \tan( \alpha ) = \tan(135) \\ \alpha = 135 \: or \frac{3\pi}{4} \\ if \:\tan( \alpha ) - \sqrt{3} = 0 \\ \tan( \alpha ) = \sqrt{3} \\ \tan( \alpha ) = \tan(60) \\ \alpha = 60 \: or \frac{\pi}{3}$