Question

Tan square theta into cos square theta is equal to one minus cos square theta

Answer 1

Hello,

Given,

(Tanθ)^2 * (cosθ)^2 =1-(cosθ)^2

LHS

We know that,

$tan \alpha = \sin( \alpha \ ) \div cos( \alpha )$

(Tanθ)^2 = (sinθ)^2/(cosθ)^2

From given eq

(sinθ)^2/(cosθ)^2*(cosθ)^2

We have

LHS=(sinθ)^2

We know that

(sinθ)^2+(cosθ)^2=1

We have,

(sinθ)^2=1-(cosθ)^2

Therefore LHS=1-(cosθ)^2

We know that, RHS =1-(cosθ)^2

Hence,

LHS =RHS

ie, (Tanθ)^2 * (cosθ)^2 =1-(cosθ)^2

Hence proved!

I hope this is clear.

Answer 2

Step-by-step explanation:

inside bracket :

Bracket 1 - tan

$tan ^{2} = sin^{2} \div cos^{2}$