Question

tan square theta=sec square theta-1​

Answer 1

Step-by-step explanation:

${ \tan(theta) }^{2} = { \sec(theta) }^{2} - 1 \\ L. H.S= > \\ \frac{ { \sin(theta) }^{2} }{ { \cos(theta) }^{2} } .........(1) \\ R. H.S= > \\ \frac{1}{ { \cos(theta) }^{2} } - 1 \\ \frac{1 - { \cos(theta) }^{2} }{ { \cos(theta) }^{2} } \\ \frac{ { \sin(theta) }^{2} }{ { \cos(theta) }^{2} } \\ { \tan(theta) }^{2} \\ \\ hope \: it \: helps \: uh$