Tan square theta upon sec square theta equal to sin theta
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tan2 theta = sin2theta / cos2 theta
sec2theta = 1/ cos2 theta
so.
sin2theta upon cos2theta / 1upon cos2theta
cos2theta would cancel with cos2theta
so...remaining is sin theta
sec2theta = 1/ cos2 theta
so.
sin2theta upon cos2theta / 1upon cos2theta
cos2theta would cancel with cos2theta
so...remaining is sin theta
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tan2(θ)/sec2(θ) can be rewritten as
(sin2(θ)/cos2(θ))/(1/cos2(θ))
Which can be simplified to (sin2(θ)*cos2(θ))/cos2(θ)
Cancelling out the cos2(θ)
Means it is equal to sin2(θ)... not sin(θ)
(sin2(θ)/cos2(θ))/(1/cos2(θ))
Which can be simplified to (sin2(θ)*cos2(θ))/cos2(θ)
Cancelling out the cos2(θ)
Means it is equal to sin2(θ)... not sin(θ)
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