Question

√tan tan +tan cot / sec sec − sin ^2 cos ^2 = tan A

Answer 1

Answer:

solved

Step-by-step explanation:

√tan A tanA +tanA cotA / secA sec A− sin ^2A cos ^2A

=  √tan² A  +tanA cotA / sec²A − sin²A cos²A

=  tan A  + 1 / sec²A − sin²A cos²A

= tan A  + 1 / sec²A −  cos²A( 1 - cos²A)

= tan A  + 1 / sec²A −  cos²A + cos^4A

= tan A  + cos²A −  cos²A + cos^4A

= tan A   + cos^4A

= tan A  

cos A = 0

A = π/2 ± 2nπ , n is an integer