tan teta = 3/4, find the value of cos teta + sin teta / cos teta – sin teta
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Since,
tan = 3/4 and tan = perpendicular/Base
P = perpendicular = 3
B = Base = 4
Using pythagoras ,
H = sqrt (p^2 + b^2)
H= 5
Calculation :
(Cos + Sin) / Cos - Sin
Cos = b/h = 4/5
Sin = p/h = 3/5
Putting these value in equation,
We get,
=(4/5 + 3/5) / (4/5 - 3/5)
= 7/1
Answer = 7
tan = 3/4 and tan = perpendicular/Base
P = perpendicular = 3
B = Base = 4
Using pythagoras ,
H = sqrt (p^2 + b^2)
H= 5
Calculation :
(Cos + Sin) / Cos - Sin
Cos = b/h = 4/5
Sin = p/h = 3/5
Putting these value in equation,
We get,
=(4/5 + 3/5) / (4/5 - 3/5)
= 7/1
Answer = 7
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