Question

Tan theeta =cos 11°+sin11°÷cos 11°-sin11° and theeta is in the third quadrant,find theeta

Answer 1

Answer:

$\tan( \alpha ) = \frac{ \cos(11) + \sin(11) }{ \cos(11) - \sin(11) }$

dividing numerator denominator by cos 11°

$\tan( \alpha ) = \frac{1 + \tan(11) }{1 - \tan(11) } = \frac{ \tan(225) + \tan(11) }{1 - \tan(225) \tan(11) } = \tan(225 + 11) = \tan(236)$

$i.e \: \alpha = 236$