Tan theeta =cos 11°+sin11°÷cos 11°-sin11° and theeta is in the third quadrant,find theeta
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Answer:
tan theeta = cos11° + sin11° / cos11° - sin11° × cos11° + sin11°/cos11° + sin11°
RHS
(cos11°+sin11°)^2 / cos^211° - sin^211°
(cos11° + sin11°) (cos11° + sin11°) / (cos11°- sin11°) ( cos11° + sin11°)
(cos11° + sin11°) / ( cos11° - sin11°)
(cos11° + ( 1 - cos11°) / (cos11° - (1- cos11°)
= 1/1 = 1.
LHS
tan 11°
= sin11°/ cos11°
= (1 - cos11°) / cos11°
= 1.
LHS = RHS
HENCE PROVED.
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