Math, asked by suryasamantakamani, 7 months ago

Tan theeta =cos 11°+sin11°÷cos 11°-sin11° and theeta is in the third quadrant,find theeta

Answers

Answered by Anonymous
2

Answer:

tan theeta = cos11° + sin11° / cos11° - sin11° × cos11° + sin11°/cos11° + sin11°

RHS

(cos11°+sin11°)^2 / cos^211° - sin^211°

(cos11° + sin11°) (cos11° + sin11°) / (cos11°- sin11°) ( cos11° + sin11°)

(cos11° + sin11°) / ( cos11° - sin11°)

(cos11° + ( 1 - cos11°) / (cos11° - (1- cos11°)

= 1/1 = 1.

LHS

tan 11°

= sin11°/ cos11°

= (1 - cos11°) / cos11°

= 1.

LHS = RHS

HENCE PROVED.

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