Question

tan theta=12/13 then evaluate 2 sin theta× cos theta/ cos^2 theta- sin^2 theta.

Answer 1

here's your answer
sin2x÷cos2x=tan2x

Answer 2

Answer:

312/25

Step-by-step explanation:

Given that

tan $\theta$ = 12/13

To Evaluate

$\frac{2 Sin\theta \  Cos\theta}{Cos^2\theta - Sin^2\theta}$

Divide Numerator and Denominator by $Cos^2\theta$

$\frac{\frac{2 Sin\theta \  Cos\theta}{Cos^2\theta} }{\frac{Cos^2\theta - Sin^2\theta}{Cos^2\theta} }$

=> $\frac{2 tan\theta}{1 - tan^2\theta}$

=> $\frac{2 *\frac{12}{13}}{1 - (\frac{12}{13})^2 } \\ \\= > \frac{ \frac{24}{13} }{1 - \frac{144}{169} }\\\\=> \frac{\frac{24}{13} }{\frac{25}{169} } \\\\=> \frac{24}{13} * \frac{169}{25} \\\\=> \frac{312}{25}$