Tan theta =24÷7 then find vale of sec theta + cosectheta (theta is acute)
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Step-by-step explanation:
Given tan θ = 8/15
θ is an acute angle
in the figure triangle OMP is a right angled triangle,
∠M=900 and ∠Q=θ
tanθ=PM/OL=8/15
Therefore, PM = 8, OM = 15
But OP2=OM2+PM2 using Pythagoras theorem,
=152+82
= 225 + 64
= 289
=172
Therefore, OP = 17
secθ=OP/OM
= 17/15
cosecθ=OP/PM
= 17/8
Now,
secθ+cosecθ = (17/15) + (17/8)
= (136 + 255)/ 120
= 391/120
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