Question

Tan theta =3 find tan 3 theta

Answer 1

Answer:

We have find here the value of $tan\theta$

And the result is $\dfrac{9}{13}$

Step-by-step explanation:

Given:

$tan\theta = 3$

And we have to find the value of $tan3\theta$

Here formula of $tan3x$ has been given below:

$tan3x=\dfrac{3\,tanx-tan^3x}{1-3\,tan^2x}$

Substituting the value of $tan3x$ in terms of $tan3\theta$.

$tan3\theta = \dfrac{3\,tan\theta-tan^3\theta}{1-3\,tan^2\theta}$

We may write as:

$= \dfrac{3tan\theta-(tan\theta)^3}{1-3(tan\theta)^2}$

substituting the value of $tan\theta = 3$

Hence:

$= \dfrac{3\times 3-(3)^3}{1-3\times (3)^2} \\=\frac{9-27}{1-27}$

$=\dfrac{-18}{-26}$

$=\dfrac{18}{26}$

$=\dfrac{9}{13}$

Answer 2

Hii

9/13

Answer

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