tan theta = 6 /15 hai to cosec theta =?
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√29/2 is the right answer
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Answer:
____________________________
_________
_____
Tanθ=>6/15=>P/B
P=>6,B=>15
____________
By Pythagoras theorem
H^2=P^2+B^2
=>(15)^2+(6)^2
=>225+36
=>261
H=>3√29
____________
Cosecθ=>H/P
=>3√29/6
=>√29/2
hope helps✊
Mark brainliest⭐
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