Question

Tan theta = (a-b)/(a+b). Find Sin theta?

Answer 1

so given height of a right angle triangle = a - b
  given base of a right angle triangle = a +b
use Pythagoras theorem we get 
hypotenuse = √{(a - b)² + (a + b)²}
                  = √{2(a² + b²)}


so sin θ=
 (a - b)/√{2(a² + b²)}

Answer 2

given height =a-b given base=a square + b square using phythogorus theorum sin = a-b/root{2(a square + b square)}