Question

tan theta =a÷b find the value of cos theta+sin thita÷cos theta -sim theta​

Answer 1

tan@ = a/b

sec²@ -tan²@ = 1

sec²@ = 1+ a²/b² = b²+a² /b²

sec@ = √a²+b²/b

cos@ = 1/sec@ = b/√a²+b²

tan@ = sin@/cos@

sin@ = tan@ × cos@

= a/b × b/√a²+b² =

sin@ = a/√a²+b²

we have to find the value of

cos@ +sin@ ÷ cos@ -sin@

b/√a²+b² + a/√a²+b²

= ---------------------------------------------

b/√a²+b² - a/√a²+b²

a+b /√a²+b²

= ------------------

b-a /√a²+b²

= a+b /√a²+b² × √a²+b²/b-a

= a+b / b-a