Question

(tan theta. cosec theta) whole square - (sin theta. sec theta) whole square = ?​

Answer 1

Let angle theta be represented by A.

(sinA + Sec A)² + (cos A + cosec A)²

= [ (SinA CosA + 1)²/CosA ]² + [ (CosA SinA + 1)² / Sin²A ]

= (1+ SinA CosA)² * [1 / Cos²A + 1/sin²A ]

= (1 + SinA CosA)² * [ Cos²A + Sin²A]/ [cos²A * Sin²A ]

= ( 1 + SinA CosA)²/ (cosA * SinA)²

= [ 1/cosA * 1/sinA + 1 ] ²

= [ Sec A Cosec A + 1 ]²

Answer 2

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