Question

tan theta - cot theta =1 then tan^2+cot^2 =

Answer 1

Hi...☺

Here is your answer...✌

GIVEN THAT,

tanθ - cotθ = 1

Squaring both sides
We get,

tan²θ + cot²θ - 2×tanθ×cotθ = 1²

tan²θ + cot²θ - 2 = 1

tan²θ + cot²θ = 1+2

tan²θ + cot²θ = 3

Answer 2

Hey mate here is your answer............
tan theta-cot theta=1
doing whole square in every side we get,
or,tan^2 theta-2 tan theta×cot theta+cot^2 theta=1
or,tan^2 theta+cot^2 theta-2tan theta×(1/tan theta)=1
or,tan^2 theta+cot^2 theta=1+2=3
So,your answer is 3
Hope it will help you