Question

tan theta - cot theta= 5, find (tan²tetha-cot²tetha) (tan³tetha-cot³tetha)

Answer 1

Answer:

tan theta-cot theta=5

by sq and cubing,

(tan theta -cot theta)2 (tan theta-cot theta)3

(5)2 (5)3

25*125

3125

Answer 2

Step-by-step explanation:

tanO - CotO = 5

tan²O + Cot²O - 2 = 25

tan²O + Cot²O = 27

( tan²O + Cot²O + 2) - 2 = 27

(tanO + CotO)² = 29

tanO + CotO = √29

tan²O - Cot²O = 5√29

(tan³O - Cot³O) = 5(27 + 1) = 140

Now , 5√29 * 140

700√29