Math, asked by pratikshyaswain28, 5 months ago

tan theta - cot theta /sin theta cos theta = tan 2 theta - cot 2 theta

Answers

Answered by saiyedfazil
3

tano - coto /sino coso = tan^2o-cot^2o

(sino/coso - coso/sino)/sinocoso = RHS

sin^2o-cos^2o/sinocoso)/sinocoso =RHS

sin^2-cos^2o/sinocoso×sinocoso = RHS

sin^2o - cos^2o = RHS

1/cosec^2o - 1/sec^2o = RHS

tan^2o - cot^2o = tan^2-cot^2o

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