Question

tan theta divided by 1 minus cot theta + cot theta divided by 1 minus tan theta is equal to 1 + tan theta + cot theta​

Answer 1

Answer:

Step-by-step explanation:

Here is ur answer

Answer 2

Answer:

Step-by-step explanation:

let theta=x

(tanx/1-cotx)+(cotx/1-tanx)=1+tanx+cotx

LHS {tanx(-tanx)/(-tanx)(1-cotx)}+(cotx/1-tanx)

(-tan^2x/1-tanx)+(cotx/1-tanx)

(cotx-tan^2x)/(1-tanx)

(1/tanx-tan^2x)/1-tanx

1-tan^3x/tanx-tan^2x

(1-tanx)(1+tanx+tan^2x)/tanx(1-tanx)

1+tanx+tan^2x/tanx

cotx+1+tanx

1+tanx+cotx

hence proved