Question

tan theta in terms of cos theta​

Answer 1

Answer:

$tan$θ $=$ ±$\frac{\sqrt{1-cos^{2} } }{cos}$

Step-by-step explanation:

tanθ= $\frac{sin}{cos}$

$sin^{2}$θ+cos²θ=1

sinθ= ±$\sqrt{1-cos^{2} }$θ

tanθ= $\frac{sin}{cos}$ = ±$\frac{\sqrt{1-cos^{2} } }{cos}$

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Answer 2

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tan theta = √1- cos²theta/cos²theta(square root for whole) = √1-cos²theta/cos theta(square root for only numerator)