Tan theta into cot theta is equal to sec theta into x then x is equal to
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Solution :
Here I am using A instead of theta.
Given ,
tanA × cotA = secA × x
=> 1 = secA × x [ Since , tanA×cotA = 1 ]
=> x = 1/secA
=> x = cosA
•••••
Here I am using A instead of theta.
Given ,
tanA × cotA = secA × x
=> 1 = secA × x [ Since , tanA×cotA = 1 ]
=> x = 1/secA
=> x = cosA
•••••
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