tan theta is 3/4 find the value of sec theta and Cos theta
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tanθ = 3/4 … (i) [Given] Consider ∆ABC, where ∠ABC 90° and ∠ACB = θ. tan θ = AB/BC … (ii) [By definition] ∴ AB/BC = 3/4 … [From (i) and (ii)] Let AB = 3k and BC 4k In ∆ABC,∠B = 90° ∴ AB2 + BC2 = AC2 …[Pythagoras theorem] ∴ (3k) + (4k) = AC ∴ 9k2 + 16k2 = AC2 ∴ AC2 = 25k2 ∴ AC = 5k …[Taking square root of both sides]
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