tan theta - root 2sec theta = root 3 find the general value of theta
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Given: tan theta - √2 sec theta = √3
To find: the general value of theta?
Solution:
- Now we have given:
tan Ф - √2 sec Ф = √3
- Converting all to sin and cos, we get:
sin Ф / cos Ф - √2 / cos Ф = √3
sin Ф - √2 = √3 cos Ф
sin Ф - √3 cos Ф = √2
- Multiply by 1/2, we get:
sin Ф / 2 - √3 cos Ф / 2 = √2 / 2
1/2 x sin Ф - √3/2 x cos Ф = 1/√2
cos 60 x sin Ф - sin 60 x cos Ф = 1/√2
sin (Ф - 60) = 1/√2
Ф = nπ + (-1)^n(45°) + 60°
Answer:
So the general solution is: nπ + (-1)^n(45°) + 60°
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