Question

tan theta + sec theta - 1/tan theta - sec theta+1 =sec theta +tan theta prove​

Answer 1

Answer:

Here, i am holding the "THETAS" as "A".

So, we can proceed our solution as under :

(tan A + sec A - 1)/(tan A - sec A + 1)

= (tan A + sec A - sec²A + tan²A)/(tan A - sec A + 1)

= [tan A + sec A - {(sec A+tan A) (sec A - tan A)}]/[tan A - sec A + 1]

= [tan A + sec A (1 - sec A + tan A)]/(tan A - sec A + 1)

= tan A + sec A

Answer 2

Answer:

Answer attached above...

Step-by-step explanation:

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