Tan theta + sec theta minus 1 upon 10 theta minus sec theta minus 1 equal to cos theta whole upon minus 1 sin theta prove
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Given Tan theta + sec theta minus 1 upon 10 theta minus sec theta minus 1 equal to cos theta whole upon minus 1 sin theta prove
Prove that
sec theta + tan theta – 1 / tan theta – sec theta + 1 = cos theta / 1 – sin theta
- L. h.S : 1/cos theta + sin theta / cos theta – 1 / sin theta / cos theta – 1/cos theta + 1
- 1 + sin theta – cos theta / cos theta / sin theta – 1 + cos theta / cos theta
- 1 + sin theta – cos theta / sin theta – 1 + cos theta
- Multiply both numerator and denominator by 1 – sin theta
- 1 – sin theta + sin theta – sin^2 theta – cos theta + sin theta cos theta / (sin theta – 1 + cos theta) (1 – sin theta)
- Cos^2 theta – cos theta + sin theta cos theta / (sin theta – 1 + cos theta)(1 – sin theta)
- Cos theta (cos theta – 1 + sin theta) / (sin theta – 1 + cos theta ) (1 – sin theta)
- Cos theta / 1 – sin theta = R. h.S (proved)
Reference link will be
https://brainly.in/question/6523952
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