tan theta = sin theta by cos theta prove this question
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I will assume theta as A in this question.
We have,
sin A=Hypotenuse÷Base
cos A=Hypotenuse÷Perpendicular
Dividing sin and cos
sin A÷cos A=(Hypotuse÷Base)÷(Hypotenuse÷Perpendicular)
sin A÷cos A= Hypotenuse×Perpendicular÷ Hypotenuse×Base
sin A÷cos A=Perpendicular÷Base
sin A÷cos A=tan A
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