Tan theta.tan 2 theta=1 in trigonomentric equationd
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We have,
tan θ . tan 2θ = 1
⇒tan θ × 2 tan θ/1 − tan^2θ = 1
⇒2 tan2θ = 1 − tan^2θ
⇒3 tan^2θ = 1
⇒tan^2θ = 1/3
⇒tan^2θ = tan^2(π/6)
⇒θ = nπ±π6
_______________
#Be Brainly✌️
_____________
We have,
tan θ . tan 2θ = 1
⇒tan θ × 2 tan θ/1 − tan^2θ = 1
⇒2 tan2θ = 1 − tan^2θ
⇒3 tan^2θ = 1
⇒tan^2θ = 1/3
⇒tan^2θ = tan^2(π/6)
⇒θ = nπ±π6
_______________
#Be Brainly✌️
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