tan theta + tan 2 theta +tan 3 theta = tan theta tan 2 theta tan 3 theta.Find the general solution
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tan (theta)+tan (2theta)=tan (3theta)
" " + " " =tan(theta +2theta)
" " + " " = tan (theta) +tan (2 th.)
______________________ =______________________
1. 1- tan(theta)tan(2th.)
so either tan (theta)+tan(2theta)=0,or
tan(theta)=0,or tan(2theta)=0
tan(theta)+tan(2theta)=0
tan(theta)+2tan theta /1-tan^(theta)=0
3tan (theta)-tan^(theta)=0
tan(theta)€(0+- root2)
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Answer:
Step-by-step explanation:
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