tan theta × tan (90 - theta) =
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43
Tan(@-90)=Tan[-{90-@}] Here @=theta. So, Tan(@-90)=-Tan[90-@] ——(1).
As, Tan(90-x)=Cotx ,where x is any arbitrary angle. Therefore, Tan(@-90)=-Cot@ [Using(1)].
Firstly, take -ve sign as common and proceed as follows: Tan [-(90-θ)] , ———-1. { tan(90-θ) is equal to cot θ.}.
We know that, Tan(-θ) = -tanθ. So, we can write eqn1 as: -tan(90-θ) which finally gives you -cotθ. tan ( θ - 90 ).
Take -ve sign common We get, tan [-(90° - θ )] = - tan (90° - θ ) = - cot θ
Answered by
63
Answer:
Step-by-step explanation:
tan(theta)*tan(90-theta) = sin(theta)/cos(theta)*cot(theta)
tan(theta)*tan(90-theta) =sin(theta)/cos(theta)*cos(theta)/sin(theta)
tan(theta)*tan(90-theta) = 1
[sin(theta)/cos(theta)*cos(theta)/sin(theta) gets cancelled ]
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