Question

tan theta/ tan (90°- theta) + sin (90°-theta)/ cos theta = sec² theta​

Answer 1

Answer:

Proof:

Step-by-step explanation:

Consider L.H.S.

tanθ/tan(90-θ)+sin(90-θ)/cosθ

⇒ tanθ/cotθ + cosθ/cosθ     [tan(90-θ)=cotθ]

⇒ tanθ/1/tanθ + 1

⇒ tanθ*tanθ/1 + 1

⇒ tan^2θ +1 or 1+tan^θ

⇒ sec^2θ=R.H.S.                 [1+tan^2θ=sec^2θ}

Hope it helps!