Math, asked by Hani2314, 1 year ago

tan theta upon sec theta - 1 = tan theta + sec theta + 1 upon tan theta + sec theta -1 ​

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Answered by Jaat1234
0

You can find this in ncert class

Solution


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Answered by samiksha83
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1+ tan^2thetha=sec^2thetha

tan square thetha =sec square thetha -1

tan thetha ×tan thetha=(sec thetha +1)(sec thetha-1)

than thetha/(sec thetha-1)=(sec thetha +1)/tan thetha

by therom of equal ratio

tan theta /(sec theta-1)=(tan theta+sec theta+1)/(tan theta+sec theta -1)

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