Question

tan theta upon sec theta minus 1 + 10 theta upon sec theta + 1 ​

Answer 1

Answer:

Step-by-step explanation:

Here is your answer mate

Answer 2

Answer:

2cosec∅

Step-by-step explanation:

=($\frac{tan∅}{sec∅-1}$)+($\frac{tan∅}{sec∅+1}$)

= $\frac{tan∅sec∅+tan∅+tan∅sec∅-tan∅}{(sec∅-1)(sec∅+1)}$

=$\frac{2tan∅sec∅}{sec^{2} \alpha-1}$

=$\frac{2tan\alpha sec\alpha}{tan^{2}\alpha }$

=$\frac{2sec\alpha }{tan\alpha }$

=$\frac{2cos\alpha }{cos\alpha sin\alpha}$

=$\frac{2}{sin\alpha }$

=2$cosec\alpha$

Hope it will help :-)