Math, asked by senggaopurusa, 3 months ago

(tan thetha)/(sec thetha - 1) + (tan thetha)/(sec thetha +1) = 2cosec thetha​

Answers

Answered by utkarsh2choirasiya
0

Answer:

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Step-by-step explanation:

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Answered by TheBestWriter
18

sec thetha (1-sin thetha)(sec thetha+tan thetha)

=(sec thetha -sec thetha sin theta)(sec thetha+tan thetha)

=(sec thetha-sin thetha/cos theta)(sec thetha+tan

thetha)

=(sec thetha-tan theta)(sec thetha+tan thetha)

=(sec thetha)^2-(tan thetha)^2

=1

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