Question

Tan thetha + sec thetha is equal to root 3 principal solution

Answer 1

$\tan( \alpha ) + \sec( \alpha ) = \sqrt{3} \\ \tan( \alpha ) - \sec( \alpha ) = \frac{1}{ \sqrt{3} } \\ 2 \tan( \alpha ) = \sqrt{3} + \frac{1}{ \sqrt{3} } \\ \tan( \alpha ) = \frac{2}{ \sqrt{3} } \\ \sec( \alpha ) = \sqrt{3} - \frac{2}{ \sqrt{3} } = \frac{1}{ \sqrt{3} }$