Question

tan thita upon 1+ tan square thita =sin thita ×cos thita

sin 4 thita +cos 4 thita + sin 2thita ×cos2thita =(1-sin thita ×cis thita)(1+sin thita ×cis thita​

Answer 1

Answer:

$7(8)2 \times \frac{?}2. | \sqrt[5 \frac{x5 {72y5. \sqrt[533 \leqslant \beta \cot(26 - 2 \div 25) ]{?} \times \frac{?}{?} }^{?} }{?} ]{?} | {?}$