Question

tan tita - cos tita / sin tita cos tita = sec^2 tita - cosec ^ 2 tita​

Answer 1

Step-by-step explanation:

$\tan( \beta ) - \cos( \beta \ \:) \\ - - - - - - - - - \\ \sin( \beta ) . \cos( \beta ) \\ take \: tan \beta \: as \: sin \beta \div cos \beta \:$

then substract and you will get the answer.

$remember$

sec²B = 1/cos²B

cosec²B= 1/sin²B