tan (titha/2)=how much
when 180° less than Titha less than 270° and cos thita = - 3/5
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180
∘
θ<270
∘
⇒90
∘
<
2
θ
<135
∘
cos
2
θ=1−sin
2
θ=1−
25
9
=
25
16
180
∘
<θ<270
∘
cos
2
θ=
25
16
⇒cosθ=−
5
4
cos
2
2
θ
=
2
1+cosθ
=
2
1−4/5
=
10
1
90
∘
<θ/2<135
∘
cos
2
(θ/2)=
10
1
⇒cos(θ/2)=−
10
1
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