Question

tan(u+iv )=i then value of v is

Answer 1

Answer:$\frac{n pi}{2i}$

Step-by-step explanation:

Tan(u+iv)=i

Tan(-u+iv)=-i

Tan2(iv)=Tan(u+iv) + Tan(-u+iv)

Tan2(iv)=i-i

Tan2(iv)=0

Tanx=0

>>x=n pi

2(iv)=n pi

[Tex]V=\frac{n pi }{2i}[/tex]

Answer 2

Tan(u+iv )=i then value of v is




Tan(u+iv) = i
Tan(-u+iv) = (- i)
Tan2(iv)=Tan(u+iv) + Tan(-u+iv)
Tan2(iv)=i-i
Tan2(iv)=0
Tanx = 0
x = n pi
2(iv)=n pi
V = npi/2i