tan x = a/b prove that (a sinx - b cosx)/(a sinx + b cosx) = (a^2 - b^2)/ (a^2 + b^2)
Answers
Answered by
12
first taking common cosx in equation
then sinx / cosx = tanx
(a sinx/cosx - b cosx/cosx ) /(a sinx/cosx + bcosx/ cosx)
(a tanx -b)/(a tanx+b)
put the value of tanx
(a*a/b - b) / ( a*a/b +b)
(a^2 - b^2) / (a^2+b^2) proved
then sinx / cosx = tanx
(a sinx/cosx - b cosx/cosx ) /(a sinx/cosx + bcosx/ cosx)
(a tanx -b)/(a tanx+b)
put the value of tanx
(a*a/b - b) / ( a*a/b +b)
(a^2 - b^2) / (a^2+b^2) proved
vickey22:
hey naresh if any confusion ask them
Answered by
1
Answer
Step-by-step explanation:
Attachments:
Similar questions